1. 序列化相关技巧
忽略某些属性
有时候我们会有这样的需求,我们只需要序列化实体类中的一部分属性,这时候我们可以通过声明忽略掉一些我们不需要序列化的属性,有两种方式可以使用么达到这个目标:
首先,可以考虑使用JsonIgnore
特性修饰不需要进行序列化的属性,如下所示:
public class Employee{ public Guid Id { get; set; } public string FirstName { get; set; } public string LastName { get; set; } public string Email { get; set; } public decimal Salary { get; set; } public string Phone { get; set; } [JsonIgnore] public DateTime HireDate { get; set; }}
运行程序:
var employeeBean = new EmployeeBean(){ Id = Guid.NewGuid(), Name = "gyzhao", Email = "gyzhao@gyzhao.com", Salary = 10000, Phone = "13912390987", HireDate = new DateTime(2012, 2, 1)};var jsonString = JsonConvert.SerializeObject(employeeBean, Formatting.Indented);//输出://{// "Id": "69a406ad-902c-45d3-8ba7-89a09779ed52",// "Name": "gyzhao",// "Email": "gyzhao@gyzhao.com",// "Salary": 10000.0,// "Phone": "13912390987"//}
如果说你需要序列化的类有很多的属性,而你是需要使用其中的一小部分,如果使用上面的上面方式就会比较繁琐(因为需要忽略的属性太多了),这时候可以考虑使用DataContract
特性修饰被序列化的类,使用DataMember
特性修饰需要进行序列化的属性,其他没有该特性属性会被自动忽略掉。如下所示:
[DataContract]public class EmployeeBean{ [DataMember] public Guid Id { get; set; } [DataMember] public string Name { get; set; } [DataMember] public string Email { get; set; } [DataMember] public decimal Salary { get; set; } public string Phone { get; set; } public DateTime? HireDate { get; set; }}
运行程序:
var employeeBean = new EmployeeBean(){ Id = Guid.NewGuid(), Name = "gyzhao", Email = "gyzhao@gyzhao.com", Salary = 10000, Phone = "13912390987", HireDate = new DateTime(2012, 2, 1)};var jsonString = JsonConvert.SerializeObject(employeeBean, Formatting.Indented);//输出://{// "Id": "69a406ad-902c-45d3-8ba7-89a09779ed52",// "Name": "gyzhao",// "Email": "gyzhao@gyzhao.com",// "Salary": 10000.0//}
DataContract
特性和DataMember
特性都从属于:System.Runtime.Serialization
命名空间。
序列化对象时循环引用异常的解决办法
序列化一个对象时,如果该对象有一个集合属性,改集合的类型就是对象本身的话,默认序列化的方法会报一个循环引用的异常,如果需要序列化,只需声明下面的属性即可:
JsonConvert.SerializeObject(result,new JsonSerializerSettings{ReferenceLoopHandling=ReferenceLoopHandling.Serialize})
2. 反序列化相关技巧
2.1 使用匿名类型作为反序列化实体
var jsonString = @"{ 'Id': '69a406ad-902c-45d3-8ba7-89a09779ed52', 'Name': 'gyzhao', 'Salary': 10000.0, 'HireDate': '2012-02-01T00:00:00' }";var employee = new { Name = default(string), Salary = default(decimal), HireDate = default(DateTime), Id = default(Guid) };var employeeBean = JsonConvert.DeserializeAnonymousType(jsonString, employee);
3. 创建JSON
//命令式的创建JSON对象 var array = new JArray(); var text = new JValue("Manual text"); var date = new JValue(DateTime.Now); array.Add(text); array.Add(date); Console.WriteLine(array.ToString()); //使用声明式的语法 var rss = new JObject( new JProperty("channel", new JObject( new JProperty("title", "James Nexton-king"), new JProperty("link", "http://james.newtonking.com"), new JProperty("description", "James Newton-Kin's blog."), new JProperty("item", "BB")))); Console.WriteLine(rss.ToString()); //通过一个匿名对象创建JSON JObject o = JObject.FromObject(new { channel = new { title = "James Newton-king", link = "http://james.netwoing.com", item = new List() { "A", "B", "C", "D", "E" } } }); Console.WriteLine(o.ToString());